Assuming names are independent variables (safe assumption) and even distribution of each letter across last names (unsafe assumption b/c I'm sure there are far fewer Z names, for example), it is 0.00022%. About the same chance as a person has of being struck by lightning (1 in 500,000).
What are the odds of having Zook and Zaunbrecher on the same staff? Pretty good if they met from getting seated by alphabetical order at a football seminar. Ok I made that up lol
So many more factors that go into it than that, how many of those 9% of last names that start with "M" are coaches and of those how many of them are college football coaches football , then of those how many are available at the time of our coaching vacancies? The odds that we hired 4 straight coaches that start with the letter "M" are astronomical. It's just crazy
Same odds in retrospect of us beating LSU with Z&Z using the bubble screen. (saban coached Nat Championship year 2003)